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10-15-2020, 10:06 AM | #11 |
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Re: Mineshaft determination
At 87 cars it's 43 we got schooled at VMP 2 weeks ago . I disagree with it but Gendora had the last word
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10-15-2020, 11:15 AM | #12 | |
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Re: Mineshaft determination
Quote:
For an odd number of cars, the #1 overall qualifier gets a bye run and the #2 overall qualifier runs the #1 qualifier of the bottom half of the ladder. By proxy, the #2 qualifier will identify the top qualifier of the bottom half of the ladder. Jeff gave a simple mathematical example how to determine this. Using an 87 car qualifying sheet you would round up the the next number of 88 then divide by 2 = 44 then you add 1 to that number to get 45. In my example of an 87 car field for mineshaft calculations the number 45 qualifier would make the determination. This can be verified with this link. http://sacramentoraceway.com/wp-cont...1/Sptm8588.pdf Ken mentioned that someone said it was number 43 at VMP, but was that a typo? Did you mean 45? You can verify on the ladder that I linked that number 43 would fall into the top half because they were paired with number 86 for the first round. It doesn't appear that the VMP race on October 3rd would be a mineshaft race since number 45 was only -.845 |
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10-15-2020, 11:45 AM | #13 |
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Re: Mineshaft determination
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