Need a little Math Help - Page 2

Spyphish · 05-18-2015, 05:38 PM

Jeff, you need Jethro!!! Remember when Jed asked him to cipher since he was in Beverly Hills school.

Naught plus naught = naught
Naught minus naught = naught
Naught times naught = naught

Naught divided by naught = naught??????

Not really, that's undefined. But it made a great show.

See you in two weeks at BR?

Larry Sullivan · 05-18-2015, 05:39 PM

Quote:

Originally Posted by HawkBrosMav

I also got .547 inches..

Not to completely over complicate things but I've always wanted to know what others think about how the difference in speeds of the 2 cars would change this calculation? Or if we know one or both guy(s) was/were on the brakes does the computer system give us enough info to accurately calculate this distance? Would we not actually want to know the rate of acceleration not the measured MPH to get this distance totally correct? or am I just over thinking it?

the .547 in a very good estimate to me but is it truly the distance between the 2 cars when the first one crosses the finish line?

Brad

All you need is the speed of the losing car since that''s how far he was behind when the winner broke the beam. Assuming the speed isn't changing very much in the last 66 feet, of course.

Greenlight · 05-18-2015, 06:25 PM

Remember, that the speed is now calculated as an average speed using timers at a distance 66 feet before the finish line, and the timer at the finish line.

So, he was probably actually going quicker than 141.5 at the finish line.

But, using 141.5 mph = 207.5383 ft/sec.

2/10000 seconds times 207.5383 ft/sec = 0.041508 ft.

0.041508 ft times 12 inches/ft = 0.498 inches.

At 143 MPH it is 0.503 inches.

*In the old days there was a timer 66 ft. before the finish line and one 66 ft. after the finish line. The average time was a lot closer to the actual finish line MPH back then.

SSDiv6 · 05-18-2015, 08:34 PM

Taking into consideration the car is accelerating, the result is 0.4980 inches.

Bobby Brannon · 05-18-2015, 09:03 PM

Just saying. 3856 MOV. 3/4" of inch
but I am old

HR9121 · 05-18-2015, 10:22 PM

A little more than a split frog's hair would be a guesstimate.

dartman · 05-19-2015, 02:26 PM

the answer is 0.50336

Frank B. · 05-19-2015, 05:09 PM

My answer is at 141.58 for the second car to cross with a MOV of .00022 the distance would be .548197 or 8.7711 16s of an inch. I stayed at a Holiday Inn Express last night also.lol

John Dinkel · 05-19-2015, 05:44 PM

At that speed how much Labatt beer can you drink?

tim worner · 05-19-2015, 06:21 PM

After a lot of deliberation I would say it was pretty darn close.

05-18-2015, 05:38 PM	#11
Spyphish Senior Member Join Date: Aug 2010 Posts: 846 Likes: 16 Liked 679 Times in 180 Posts	Re: Need a little Math Help Jeff, you need Jethro!!! Remember when Jed asked him to cipher since he was in Beverly Hills school. Naught plus naught = naught Naught minus naught = naught Naught times naught = naught Naught divided by naught = naught?????? Not really, that's undefined. But it made a great show. See you in two weeks at BR?

05-18-2015, 06:25 PM	#13
Greenlight Member Join Date: Dec 2004 Posts: 215 Likes: 16 Liked 79 Times in 22 Posts	Re: Need a little Math Help Remember, that the speed is now calculated as an average speed using timers at a distance 66 feet before the finish line, and the timer at the finish line. So, he was probably actually going quicker than 141.5 at the finish line. But, using 141.5 mph = 207.5383 ft/sec. 2/10000 seconds times 207.5383 ft/sec = 0.041508 ft. 0.041508 ft times 12 inches/ft = 0.498 inches. At 143 MPH it is 0.503 inches. *In the old days there was a timer 66 ft. before the finish line and one 66 ft. after the finish line. The average time was a lot closer to the actual finish line MPH back then.

05-18-2015, 08:34 PM	#14
SSDiv6 VIP Member Join Date: Feb 2003 Location: Glendale, Arizona Posts: 3,045 Likes: 712 Liked 1,594 Times in 583 Posts	Re: Need a little Math Help Taking into consideration the car is accelerating, the result is 0.4980 inches.

05-18-2015, 09:03 PM	#15
Bobby Brannon Senior Member Join Date: Mar 2002 Location: Bossier City,La. Posts: 659 Likes: 3 Liked 104 Times in 35 Posts	Re: Need a little Math Help Just saying. 3856 MOV. 3/4" of inch but I am old __________________ Bobby Brannon 4705 STK, SS

05-18-2015, 10:22 PM	#16
HR9121 Live Reporter Join Date: Jan 2011 Location: New Bern, NC Posts: 3,467 Likes: 146 Liked 3,363 Times in 731 Posts	Re: Need a little Math Help A little more than a split frog's hair would be a guesstimate. __________________ James Williamson W200 J/SA. SS/JA

05-19-2015, 02:26 PM	#17
dartman Member Join Date: Oct 2005 Location: N.S. CANADA Posts: 498 Likes: 160 Liked 68 Times in 41 Posts	Re: Need a little Math Help the answer is 0.50336 __________________ 1231 FS/D Drag Pak 1231 E/SA 71 Demon Kelly MacKay

05-19-2015, 05:09 PM	#18
Frank B. Member Join Date: Jun 2007 Posts: 141 Likes: 0 Liked 51 Times in 25 Posts	Re: Need a little Math Help My answer is at 141.58 for the second car to cross with a MOV of .00022 the distance would be .548197 or 8.7711 16s of an inch. I stayed at a Holiday Inn Express last night also.lol

05-19-2015, 05:44 PM	#19
John Dinkel Senior Member Join Date: Nov 2005 Location: Pinckney, Michigan Posts: 507 Likes: 399 Liked 263 Times in 68 Posts	Re: Need a little Math Help At that speed how much Labatt beer can you drink? __________________ John Dinkel 3295 STK

05-19-2015, 06:21 PM	#20
tim worner Senior Member Join Date: Jan 2002 Location: duncannon Posts: 837 Likes: 14 Liked 126 Times in 20 Posts	Re: Need a little Math Help After a lot of deliberation I would say it was pretty darn close. __________________ Tim Worner SS 1747