Quote:
Originally Posted by Dissident
Easiest thing to do is calculate the square inches of area of the main secondary jet which is fixed (I use 0.135" diam = Area of 0.014313915 sq in) then subtract the area of the secondary metering rod tip so the difference is the functional area of the secondary jet with that metering rod. As an example, the guy that raced his SS in Atlanta said he used a 0.057" and a 0.066" tipped rod so that is a change of area of 30%.....wow. Normally one would want to change only about 5% or so at a time, but that is just a suggestion. Whatever works for you.
Best thing to do is to make a chart or table of whatever your metering rod tip selection is and do the arithmetic.
Regards to all that like this kind of stuff. 
Otherwise just put your mask on and change the channel to reruns. 
HB2 
Dissident |
Yes a large change in metering rod area but a much small % change in total flow area.
► ((.057/2)^2*pi)/((.066/2)^2*pi) = 0.7458678
► ((.066/2)^2*pi)/((.057/2)^2*pi) = 1.34072022
Stan